Answer:
1.344 N
Explanation:
The expression for the for on a wire carrying current in a magnetic field is given as,
F = BILsinФ.................... Equation 1
Where F = Force on the wire, B = magnetic field, I = current, L = Length of the wire, Ф = angle between the conductor and the magnetic field.
Given: B = 0.15 T, I = 3.2 A, L = 0.8 m, Ф = 90° (perpendicular)
Substitute into equation 1
F = 0.15(3.2)(0.8)(sin90°)
F = 1.344 N
Hence the Force on the wire = 1.344 N
