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  • 08-08-2016
  • Physics
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A certain reaction has an activation energy of 67.72 kJ/mol. At what Kelvin temperature will the reaction proceed 4.00 times faster than it did at 353 K?

Respuesta :

Hussain514 Hussain514
  • 09-08-2016
T1 = 363 K 
T2 = ?? 
R = 8.3145 J/mol K 
K1 = 1 
K2 = 4 
Ea = 67.72 x 1000 = 67720 J/mol

T2 =1 / (1/363) – (8.3145 / 67720) x ln(4 / 1)

T2 = 1/
0.00258461502
T2 = 386.90 K
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