jlew7istEdmsgom
jlew7istEdmsgom jlew7istEdmsgom
  • 08-08-2016
  • Mathematics
contestada

Find the exact value of the real number y.

y = csc^-1(1)

Respuesta :

pinquancaro pinquancaro
  • 03-07-2019

Answer:

The exact value of the real number y is [tex]y=\frac{\pi}{2}[/tex]                      

Step-by-step explanation:

Given : Expression [tex]y=\csc^{-1}(1)[/tex]

To find : The exact value of the real number y?

Solution :

We can write the expression as

[tex]y=\csc^{-1}(1)[/tex]

[tex]\csc y=1[/tex]

[tex]\frac{1}{\sin y}=1[/tex]

[tex]\sin y=1[/tex]

[tex]\sin y=\sin (\frac{\pi}{2})[/tex]

[tex]y=\frac{\pi}{2}[/tex]

Therefore, The exact value of the real number y is [tex]y=\frac{\pi}{2}[/tex]

 

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