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  • 06-05-2020
  • Chemistry
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Please help!!!

A molecule contains 47.30 g mercury (Hg) and 16.70 g chlorine (Cl). What is its empirical formula?

Please helpA molecule contains 4730 g mercury Hg and 1670 g chlorine Cl What is its empirical formula class=

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Eduard22sly
Eduard22sly Eduard22sly
  • 11-05-2020

Answer:

Option B. HgCl2

Explanation:

Data obtained from the question include:

Mass of Mercury (Hg) = 47.3g

Mass of chlorine (Cl) = 16.7g

The empirical formula for the compound can be achieved by doing the following:

Step 1:

Divide by their individual molar mass

Hg = 47.3/201 = 0.235

Cl = 16.7/35.5 = 0.470

Step 2:

Divide by the smallest to express in whole number:

Hg = 0.235/0.235 = 1

Cl = 0.470/0.235 = 2

Therefore, the empirical formula is HgCl2

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