Answer:
= 1.7 M
Explanation:
Molecular mass of NaCl = ( 23+35.5 ) = 58.5g
58.5g of NaCl are weighed by 1 mole of NaCl
10.0g of NaCl will be weighed by ( 10÷58.5 )
= 0.17 moles of NaCl
100mL = ( 100÷1000)L = 0.1L
0.1L of a solution is occupied by 0.17 moles of NaCl
1L of solution will be occupied by [(1÷0.1)×0.17]
=1.7 M
