Respuesta :
Answer:
Mean increased
Median remains same
Step-by-step explanation:
Suzanne make $ 100 k per year
5 other employee  $ 40 k  to $ 50 K per year per employee
data in ascending order
$40000  , $40000+a  , $40000+b  , $40000+c   , $50000  , $ 100000
where 10000 ≥c ≥ b ≥ a ≥ 0
Mean = ($40000 + $40000+a + $40000+b  + $40000+c  + $50000 + $ 100000) /6
Mean = $(310000 + a + b + c)/ 6
Median = ($40000+b  + $40000+c )/2 =  $40000 + (b+c)/2
Suzanne make now $ 100000 + $ Â 30000 = $ 130000 per year
$40000  , $40000+a  , $40000+b  , $40000+c   , $50000 , $ 130000
Mean = ($40000 + $40000+a + $40000+b  + $40000+c  + $50000 + $ 130000) /6
Mean = $(340000 + a + b + c)/ 6
Median = ($40+b k + $40+c k)/2 = Â $40 + (b+c)/2 k
Mean increased by  $(340000 + a + b + c)/ 6 - $(310000 + a + b + c)/ 6
= $ 30000/6 Â = $ 5000
Median Remains the same