wilsonbuddo
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  • 06-05-2020
  • Computers and Technology
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what is the molarity of a solution prepared by dissolving 15.0g of sodium hydroxide in enough water to make a total of 225 ml of solution​

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mahesh11
mahesh11 mahesh11
  • 06-05-2020

Answer:

1.6666 g/mol = 1 [tex]\frac{2}{3}[/tex] g/mol

Explanation:

Molar mass of NaOH= 23+16+1 =40g/mol

Mols in 15g = 15/40 mol

If this was dissolved in 225ml of water molarity of the solution is

[tex]\frac{15}{40}[/tex] ÷ 225 x 1000 = 1.6666 g/mol = 1 [tex]\frac{2}{3}[/tex] g/mol

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