Answer:
Roughly 323g of H2O.
Explanation:
Balance your chemical equation:
1 Fe3O4 + 4H2 → 3 Fe + 4 H2O
Modulate your stoichiometry 4 steps:
[tex]750g \times \frac{1mol}{55.8g} \times \frac{4mol}{3mol} \times \frac{18g}{1mol} = \\ = \frac{54000}{167.4} = \\ = 322.581g[/tex]
