Answer:
y = e²x
Step-by-step explanation:
Using the rules of logarithms
log y - log x = log ([tex]\frac{y}{x}[/tex] )
[tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex]
Given
ln(y) = ln(x) + 2 ( subtract ln(x) from both sides )
ln(y) - ln(x) = 2
ln ([tex]\frac{y}{x}[/tex] ) = 2
[tex]\frac{y}{x}[/tex] = e² ( multiply both sides by x )
y = e²x
