Answer:
63
Step-by-step explanation:
This sum (from n = 1 to n =6 of 128(1/2)^n can be found in several ways. Since there are only a few numbers here to add together, we can just write out the given sum as
128(1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64), or
64 + 32 + 16 + 8 + 4 + 2 + 1, which sums up to 63.
