Answer:
22.6881 Grams of CO
Explanation:
Fe2O3 + 3CO = 3CO2 + 2Fe
Ratio
1:3 = 3:2
How many grams of CO are needed to produce 30.2 grams of Fe
Fe2O3 Molar mass: 159.69 g/mol
CO Molar mass: 28.01 g/mol
Fe Atomic mass: 55.845
Ok so our end result is 30.2 Grams of Fe, we have 2 Fe so we have 15.1 Grams per Fe
15.1/55.845 = 0.27
So then we multiply this by 3 as we we know the ratio and get get 0.81 required as this is 3CO.
So we need 0.81 Moles of CO so we need 22.6881 Grams of CO.
