Answer:
2.
Step-by-step explanation:
To find the number of trailing zeroes, given n!, we take n and divide it by increasing powers of 5. For example, the number of trailing zeroes in 50! = 50/5 = 10, 50/25 = 2, 10 + 2 = 12 trailing zeroes.
In this case, 10/5 = 2, and since we cannot get an integer from dividing 10 and 25, we are left with this answer.
I hope this helps!
