mattgolombisky7991 mattgolombisky7991
  • 11-06-2020
  • Mathematics
contestada

2) The fish population in a local stream is decreasing at a rate of 3% per year. The population in 2005 was 48,000. What is the population now?

Respuesta :

jmonterrozar
jmonterrozar jmonterrozar
  • 14-06-2020

Answer:

30396 fish.

Step-by-step explanation:

We are in 2020, that is, 15 years have passed since 2005, to calculate the population it would be:

The first year there would be 48,000, then each year it decreases by 3%, that is, the first one was like this:

48000 - 48000 * 0.03

That is to say:

48000 * (1 - 0.03)

Now, depending on the year number it would be:

48000 * (1-0.03) ^ n

But how were 15 years n = 15, then:

48000 * (1-0.03) ^ 15 = 30396.057

The fish population would be 30396 fish.

Answer Link

Otras preguntas

Which idea did Descartes contribute to the Scientific Revolution?
Mother Fletcher´s Gift Conflict
State two ways of reducing the drag forces on a bicycle
9.How did immigration change during the period between the Civil War and the early 1900s?
What is the first thing you should do if an accident occurs in your classroom? A. Find the emergency equipment. B.Notify your teacher. C.Go to the nearest hospi
compare and contrast deposition caused by wind with deposition caused by moving water.
218 rounded to nearest ten435 pounds rounded to nearest hundred pound 739 is closer to              that is to              .739 rounded to nearest hundred
How does one determine when an ecosystem is in "balance"?
What two numbers multiply to 630 and add to -57
What TWO factors determine gravitational potential energy?
good job