Answer:
[tex]x>2\left(y-2\right)[/tex]
Step-by-step explanation:
[tex]4y-2x<8\\\mathrm{Subtract\:}4y\mathrm{\:from\:both\:sides}\\4y-2x-4y<8-4y\\Simplify\\-2x<8-4y\\\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}\\\left(-2x\right)\left(-1\right)>8\left(-1\right)-4y\left(-1\right)\\Simplify\\2x>-8+4y\\\mathrm{Divide\:both\:sides\:by\:}2\\\frac{2x}{2}>-\frac{8}{2}+\frac{4y}{2}\\Simplify\\x>2\left(y-2\right)[/tex]
