1. A game is played by spinning a wheel that contains the words Win and Lose. The wheel has 10 slots, with Win written four times and Lose written six times. If the wheel lands on win, you win
$5; on lose, you win nothing. It costs $2 to play. What is the expected value?

Picker Wheel is a wheel spinner for a random picker. Various functions & customization. Enter choices or names, spin the wheel to decide a random result.

We have

If the wheel lands on win, you win $5;

on lose, you win nothing.

It costs $2 to play.

According to the question

Win written four times and Lose written six times.

P (W) = 4/10 = 0.4

P (L) = 6/10 = 0.6

x net p(x) xP(x)

Win 5 - 2 = 3 0.4 1.2

Loose 0 - 2 = -2 0.6 -1.2

∑xP(x) = 1.2 - 1.2 = 0

Hence , expected value of profit or loss is ZERO

or

You can say expected value is 2 $ against 2$ cost

5(0.4) + 0(0.6) = 2 against 2 $ ticket.

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https://brainly.com/question/51837427

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1. A game is played by spinning a wheel that contains the words Win and Lose. The wheel has 10 slots, with Win written four times and Lose written six times. If the wheel lands on win, you win $5; on lose, you win nothing. It costs $2 to play. What is the expected value?

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What is spinning wheel game?

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1. A game is played by spinning a wheel that contains the words Win and Lose. The wheel has 10 slots, with Win written four times and Lose written six times. If the wheel lands on win, you win
$5; on lose, you win nothing. It costs $2 to play. What is the expected value?