Answer:
HL
Step-by-step explanation:
[tex] In\: right \triangle 's DAB \: \&\: CBA\\
\angle DAB \cong \angle CBA... (each 90\degree) \\ hypotenuse \: DB \cong hypotenuse \: CA. (given) \\
side AB \cong side BA.. (common) \\
\therefore \triangle DAB \cong \triangle CBA.. (By \: RHS\: or \: HL \: Postulate) [/tex]
