Answer:
[tex]\boxed{\sf \ \ \ maximum \ is \ 11^9=2357947691 \ \ \ }[/tex]
Step-by-step explanation:
hello
[tex]y = 11^{(6x-x^2)}=exp((6x-x^2)ln(11))[/tex]
so to know the maximum to y we can check the maximum of
f(x)=[tex]6x-x^2[/tex]
f is derivable and f'(x)=6-2x
f'(x)=0 <=> x = 3
so the maximum is reached for x = 3
f(3)=18-9=9
and then
[tex]y = 11^9=2357947691[/tex]
to be rigorous, we can write the variation table of y to show that there is only one maximum
hope this helps
