Answer:
c = 0.38 J/g °C
Step-by-step explanation:
We have,
Mass of metal X is 95.4 g
Initial temperature was 25°C and final temperature is 48°C.
The metal absorbs 849 J of heat
The heat absorbed due to change in temperature is given by :
[tex]Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{849}{95.4\times (48-25)}\\\\c= 0.38\ J/g^{\circ} C[/tex]
So, the specific heat of metal X is 0.38 J/g °C.
