Answer:
210°
Step-by-step explanation:
By inscribed angle theorem:
[tex] m\angle DFG = \frac{1}{2} \times m\widehat{(EDG)} \\\\
105\degree = \frac{1}{2} \times m\widehat{(EDG)} \\\\
105\degree\times 2= m\widehat{(EDG)} \\\\
\huge \red {\boxed {\therefore m\widehat{(EDG)} = 210\degree}} [/tex]
