Answer:
The center of mass velocity is  [tex]v = 32.25 \ m/s[/tex]
Explanation:
From the question we are told that
     The mass of the cylinder is  [tex]m = 2.50 \ kg[/tex]
      The radius  is  [tex]r = 2.18 \ cm = 0.0218 \ m[/tex]
       The length is  [tex]l = 2.7 \ cm = 0.027 \ m[/tex]
       The height of the plane is  h  = 79.60  m
        and the distance covered is  [tex]d = 4.64 \ m[/tex]
The center of mass velocity o the cylinder when it reaches the bottom is mathematically represented as
       [tex]v = \sqrt{\frac{4gh}{3} }[/tex]
substituting values Â
        [tex]v = \sqrt{ \frac{4 * 9.8 * 79.60}{3} }[/tex]
       [tex]v = 32.25 \ m/s[/tex]
