Ohm's Law for electrical circuits is stated VequalsRI, where V is a constant voltage, R is the resistance in ohms and I is the current in amperes. Your firm has been asked to supply the resistors for a circuit in which V will be 9 volts and I is to be 5 plus or minus 0.1 amperes. In what interval does R have to lie for I to be within 0.1 amps of the target value Upper I 0 equals 5 question mark

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okpalawalter8 okpalawalter8 · Answer 1 · 2020-07-13T02:31:10+02:00

Answer:

The resistance interval is [tex]R = 1.8 \pm 0.037[/tex]

Explanation:

From the question we are told that

The voltage is V = 9 V

The current is [tex]I = 5 \pm 0.1[/tex]

The maximum current would be

[tex]I_{max} = 5 + 0.1 = 5.1 \ A[/tex]

The minimum current would be

[tex]I_{min} = 5 - 0.1 = 4.9 \ A[/tex]

The maximum resistance is

[tex]R_max = \frac{V}{I_{min}}[/tex]

[tex]R_max = \frac{9}{4.9}[/tex]

[tex]R_max = 1.837 \Omega[/tex]

The minimum resistance is

[tex]R_{min} = \frac{V}{I_{max}}[/tex]

[tex]R_{min} = \frac{9}{5.1}[/tex]

[tex]R_{min} = 1.765 \Omega[/tex]

and [tex]R = \frac{9}{5} = 1.8 \Omega[/tex]

The interval R lies is

[tex]R = 1.8 \pm 0.037[/tex]