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Randolph is trying to find the equation of a line parallel to y = '1 over 4 x βˆ’ 6 in slope-intercept form that passes through the point (βˆ’1, 5). Which of the following equations will he use? (6 points) y βˆ’ 5 = 1 over 4 (x βˆ’ (βˆ’1)) y βˆ’ (βˆ’1) = 1 over 4 (x βˆ’ 5) y βˆ’ 5 = βˆ’4(x βˆ’ (βˆ’1)) y βˆ’ (βˆ’1) = βˆ’4(x βˆ’ 5)

Respuesta :

Answer:

A. y-5 = 1/4(x+1)

Step-by-step explanation:

The equation of a line parallel to the line y = 1/4x - 6 and passing through the point can be expressed in slope-intercept form of the equation

y-yβ‚€ = m(x-xβ‚€) where;

(xβ‚€, yβ‚€) is the given point

m is the slope of the unknown line.

Since the unknown line is parallel to the given line Β y = 1/4x - 6, they will have the same slope.

Let us get the slope of the known line Β y = 1/4x - 6

Comparing the line Β y = 1/4x - 6 with the standard equation of a line Β 

y = mx + c, the slope of the known line m = 1/4.

The slope of the unknown line is also equivalent to 1/4.

Substituting the given point Β (βˆ’1, 5) and the calculate slope m into the slope-intercept form of the equation y-yβ‚€ = m(x-xβ‚€);

xβ‚€ = -1, yβ‚€ = 5 and m = 1/4

Hence, the equation that Randolph is trying to find will be y-5 = 1/4(x-(-1)) i.e Β y-5 = 1/4(x+1)

Answer:

A, here is a pic of the actual question ;)

Step-by-step explanation:

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