Answer:
Fe = 2.4 × 10^10 N
Explanation:
Given the following :
q1 = charge 1 = 0.0072 C = positive direction
q2 = charge 2 = 0.0060 C = - ve direction
r = distance = 0.0040
Using the relation :
Fe = K(q1q2) /r^2
Where K = columb's constant = 9×10^9 Nm^2/C^2
Fe = electric force
Fe = 9×10^9(0.0072 * 0.0060) / 0.0040^2
Fe = [9×10^9 (0.0000432)] / 0.000016
Fe = 388,800 / 0.000016
Fe = 24300000000
Fe = 2.43 × 10^10 N
