Answer:
toaster- 15.1A
electric frying pan- 11.8 A
lamp- 0.5 A
b) The combination will blow the fuse.
Explanation:
When devices are connected in parallel, the potential difference across each of the devices is the same but the current through each is different. Hence;
V= 120 V
Power= IV
For the toaster;
I= 1820/120 = 15.1 A
For the electric frying pan;
I= 1420/120 = 11.8 A
For the lamp;
55/120 = 0.5 A
Total current = 15.1 +11.8 + 0.5 = 27.4 A
The combination will blow the fuse.
Explanation: Ā Ā
step one:
Given data
power of toaster= 1,820 W Ā
power of electric frying pan= 1,420 W Ā
power of lamp= 55 W Ā
current of the outlet= 15 A
voltage of outlet = 120 V
step two
since all Ā three appliances are connected in parallel to the socket outlet, they will use the same voltage of 120 V and the currents will be different across each appliance,
Hence the current across the Toaster will be Iā
using P=IāV we have
Iā= P/V
Iā= 1820/120 = Ā 15.16 A
A. The current drawn by each device
the current across the Ā electric frying pan will be Iā
using P=IāV we have
Iā= P/V
Iā= 1420/120 = Ā 11.83 A
the current across the Ā lamp will be Iā
using P=IāV we have
Iā= P/V
Iā= 55/120 = Ā 0.45 A
therefore the total current drawn by all appliances will be
Total current = Iā+Iā+Iā= 15.16 +11.83+ 0.45= 27.44
B. Ā Will this combination blow the 15-A fuse?
27.44 A > 15 A by 45% ...and this will make fuse to blow
