Respuesta :
Answer:
1) f = 214 Hz , 2)  answer is c , 3) f = 428 Hz , 4)  f₂ = 428 Hz ,  f₃ = 643Hz
Explanation:
1) A tube with both ends open, the standing wave has a maximum amplitude and a node in its center, therefore
        L = λ / 2
        λ  = 2L
        λ  = 2 0.8
        λ  = 1.6 m
wavelength and frequency are related to the speed of sound (v = 343 m / s)
        v =λ  f
        f = v / λ Â
        f = 343 / 1.6
        f = 214 Hz
2) In this case the air comes out through the open hole, so we can assume that the length of the tube is reduced
      λ' = 2 L ’
     as L ’<L₀
     λ' <λ₀
     f = v / λ'
     f' > fo
the correct answer is c
3) in this case the length is L = 0.40 m
     λ = 2 0.4 = 0.8 m
     f = 343 / 0.8
     f = 428 Hz
4) the different harmonics are described by the expression
     λ = 2L / n      n = 1, 2, 3
     λ₂ = L
     f₂ = 343 / 0.8
     f₂ = 428 Hz
     λ₃ = 2 0.8 / 3
     λ₃ = 0.533 m
     f₃ = 343 / 0.533
     f₃ = 643 Hz
4,1) as we have two maximums at the ends, all integer multiples are present
    the answer is C
E) the length of an open pipe created that has a wavelength of lam = 1.6 m is requested
in this pipe there is a maximum in the open part and a node in the closed part, so the expression
    L = λ / 4
    L = 1.6 / 4
    L = 0.4 m
the answer is C
F) in this type of pipe the general expression is
      λ = 4L / n     n = 1, 3, 5 (2n + 1)
therefore only odd values ​​can produce standing waves
      λ₃ = 4L / 3
      λ₃ = 4 0.4 / 3
      λ₃ = 0.533
      f₃ = 343 / 0.533
      f₃ = 643 Hz