Answer:
h=2 & k= –3
Step-by-step explanation:
substitute p and q into the equation :
h(–3i+j) +k(i–5j)= –9i +17j
expanding gives;
–3hi +hj + ki –5kj= –9i +17j
=>
–3h + k = –9___(1) and h – 5k = 17___(2)
from (1)
k= –9 +3h___(3) substituting into equation (2)
=>
h +45 –15h = 17
=> h= 2
substituting this value of h into (3)
=> k = –9+6= –3
therefore, h=2 and k= –3
