Answer:
Step-by-step explanation:
I take it that a and b are defined below.
y = a(x - b)^2 + c
y = (x^2 - 16x ) + 54
y = (x^2 - 16x + (16/2)^2) + 54 - (16/2)^2
y = (x - 16x + (16/2)^2) + 54 - 8^2
y = (x - 16x + 8^2) + 54 - 64
y = (x - 16x + 64) - 10
y = (x - 8)^2 - 10
This should give you a minimum. Go to Desmos and put in the original equation. It should give a minimum at 8,-10
Since I'm not entirely sure how a and be are defined, I will fill it in the way I have defined it.
a = 1
b = - 8
c = - 10
