Answer:2
Step-by-step explanation: cot2θ+cosec2θ
=[tex]\frac{cot^{2}\theta }{2cot\theta} +\frac{1}{sin^{2}\theta }[/tex]
=[tex]\frac{2^{2}-1 }{2*2} \\[/tex][tex]\frac{1}{2cot\theta}[/tex]/1+cot²θ
=[tex]\frac{4-1}{4} +\frac{1+2^{2} }{2*2}[/tex]
=[tex]\frac{3}{4} +\frac{5}{4}[/tex]
=[tex]\frac{8}{4}[/tex]
=[tex]2[/tex]
