Answer:
1) The change in momentum of the ball is 8 kgm/s
2) The total momentum of the bodies is 20 kgm/s
Explanation:
1)
Given;
mass of the ball, m = 2 kg
initial velocity of the ball, vâ = 2 m/s
final velocity of the ball, vâ = -2 m/s (the ball rebounds)
The change in momentum of the ball is given by;
ÎP = Îmv
ÎP = mvâ - mvâ
ÎP = m(vâ - vâ)
ÎP = 2(2 - (-2))
ÎP = 2(2 + 2)
ÎP = 8 kgm/s
2)
Given;
mass of the first body, mâ = 5kg
mass of the second body, mâ = 5kg
speed of the first body, vâ = 2 m/s
speed of the second body, vâ = 2 m/s
The total momentum of the bodies is given by
P = mâvâ + mâvâ
P = (5 x 2) + (5 x 2)
P = 20 kgm/s