Given :
The average of 3, 3, 16, 19 and y is 10.
To Find :
The value of y+6 .
Solution :
Mean of n numbers is given by :
[tex]M=\dfrac{\text{Sum of all numbers}}{n}[/tex]
[tex]10=\dfrac{3+3+16+19+y}{5}\\\\10=\dfrac{y+41}{5}\\\\y=9[/tex]
Therefore , the value of y+6 is 15 .
Hence , this is the required solution .
