gfelix23
gfelix23 gfelix23
  • 10-09-2020
  • Mathematics
contestada

How do i find the vertex of the equation y=(x+5)(x+4)?

Respuesta :

surjithayer10 surjithayer10
  • 10-09-2020

Answer:

Step-by-step explanation:

y=(x+5)(x+4)=x²+5x+4x+20=x²+9x+20=x²+9x+(9/2)²-(9/2)²+20

[tex]y=(x+\frac{9}{2} )^2-\frac{81}{4} +20\\y=(x+\frac{9}{2})^2-\frac{81}{4}+\frac{80}{4}\\y=(x+\frac{9}{2})^2-\frac{1}{4}[/tex]

vertex is (9/2,-1/4) or(4.5,-0.25)

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good job