Answer:
Fā = 4.29 x 10āµ N
Explanation:
The total force required to move the freight train with the given acceleration is given by the following formula:
F = ma + f
where,
F = Total Force Required from both engines = ?
m = equivalent mass of system = 2(8 x 10āµ kg) + 5.5 x 10āµ kg = 21.5 x 10āµ kg
a = required acceleration = 5 x 10ā»Ā² m/s²
f = force of friction = 7.5 x 10āµ N
Therefore,
F = (21.5 x 10ⵠkg)(0.05 m/s²) + 7.5 x 10ⵠN
F = 8.575 x 10āµ N
Now, for identical forces in each engine can be given as:
Force exerted by each engine = Fā = F/2
Fā = 8.575 x 10āµ N/2
Fā = 4.29 x 10āµ N