Answer:
[tex]log_{3}[/tex] 16
Step-by-step explanation:
Using the rule of logarithms
logx + logy = log(xy), then
[tex]log_{3}[/tex]2 + [tex]log_{3}[/tex]8
= [tex]log_{3}[/tex](2 × 8)
= [tex]log_{3}[/tex] 16
