Answer:
x = - 2, x = 9
Step-by-step explanation:
Given
f(x) = [tex]\frac{x^2-9x}{x^2-7x-18}[/tex]
The denominator of f(x) cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the values that x cannot be.
x² - 7x - 18 = 0
(x - 9)(x + 2) = 0
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
x - 9 = 0 ⇒ x = 9
The excluded values are x = - 2, x = 9
