Answer:
[tex]\huge\boxed{f^{-1}(x)=\dfrac{1}{2}x+5}[/tex]
Step-by-step explanation:
[tex]f(x)=2x-10\to y=2x-10\\\\\text{exchange x to y and vice versa}\\\\x=2y-10\\\\\text{solve for}\ y\\\\2y-10=x\qquad|\text{add 10 to both sides}\\\\2y-10+10=x+10\\\\2y=x+10\qquad|\text{divide both sides by 2}\\\\\dfrac{2y}{2}=\dfrac{x}{2}+\dfrac{10}{2}\\\\y=\dfrac{1}{2}x+5[/tex]
