saggurthig saggurthig
  • 10-11-2020
  • Mathematics
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[tex] {x}^{4 {}^{2} } {y}^{2} {z}^{9} \div {x}^{2} {y}^{2} z[/tex]
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Respuesta :

rdiussss
rdiussss rdiussss
  • 10-11-2020

This would evaluate to: [tex]\frac{x^{16} * y^2 * z^9}{x^2 * y^2 * z}\\[/tex]

Now because of the rule of division with exponents which is: [tex]x^m/x^n = x^{m - n}[/tex]

Since they are in multiplication, you can use the the rule for each variable.

So here, we apply the rule and get:

[tex]x^{16 - 2} * y^{2 - 2} * z^{9 - 1}[/tex]

2 - 2 = 0 and any real number (except 0) raised to 0 is equal to 1 so we can cancel that off.

[tex]x^{14} * y^{0} * z^{8}[/tex]

and so you finally get:

[tex]x^{14} * z ^ 8 = x^{14}z^8[/tex]

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