The concentration of the acid solution : 0.43 M
Further explanation
Reaction
Cu + 2HCl ⇒ CuCl₂ + H₂
- the amount of Cu reacting :
[tex]\tt 13.36-4.54=8.82~g[/tex]
[tex]\tt \dfrac{8.82}{63.5}=0.139[/tex]
- concentration of the acid solution(HCl) :
mol HCl :
[tex]\tt \dfrac{2}{1}\times 0.139=0.278[/tex]
concentration :
[tex]\tt M=\dfrac{mol}{V}=\dfrac{0.278}{0.65~L}=0.43[/tex]
