Answer:
OBr₂
Explanation:
The ionic character depends on the difference of electronegativity between the elements. The higher ΔEN, the greater the ionic character.
SBr₂
ΔEN = |EN(S)-EN(Br)| = |2.5-2.8| = 0.3
OBr₂
ΔEN = |EN(O)-EN(Br)| = |3.5-2.8| = 0.7
SeCl₂
ΔEN = |EN(Se)-EN(Cl)| = |2.4-3.0| = 0.6
TeI₂
ΔEN = |EN(Te)-EN(I)| = |2.1-2.5| = 0.4
SCl₂
ΔEN = |EN(S)-EN(Cl)| = |2.5-3.0| = 0.5
OBr₂ is the molecule with the most ionic character.
