xtra1234 xtra1234

10-10-2016
Mathematics

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Given the following matrices A and B, find an invertible matrix U such that UA = B:

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Nirina7 Nirina7

24-10-2016

A and B must be invertible, we have UA=B, since A is invertible. A^-1 exists, by multiplying with A^-1, we have UA A^-1 =B A^-1. But AA^-1 = I (identity matrix) and XI=X, for all matrix X, we find UI= B A^-1, and U= B A^-1.

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