Seudónimo Seudónimo
  • 10-10-2016
  • Mathematics
contestada

solve for x
ln(x-3)=ln(x+17)-ln(x-1)

Respuesta :

Аноним Аноним
  • 10-10-2016
ln(x-3)=ln(x+17)-ln(x-1)

1) ln A-ln B=ln (A/B)

ln(x-3)=ln[(x+17)/(x-1)]

Then:
x-3=(x+17)/(x-1)
(x-3)(x-1)=(x+17)
x²-x-3x+3=x+17
x²-5x-14=0

x=[5⁺₋√(25+56)]/2=(5⁺₋9)/2

We have two possible solutions:
x₁=(5-9)/2=-2
x₂=(5+9)/2=7

We must to check the possible solutions:
if x₁=-2; then;  ln(-2-3)=ln(-2+17)-ln(-2-1),  in this case this solutions is not possible, because logarithms of negative numbers are not defined.

if x₂=7; then:
ln(7-3)=ln(7+17)-ln(7-1)
 ln 4=ln 24 -ln 6
ln 4=ln 24/6
ln 4=ln 4

Answer: x=7
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