Answer:
[OH-] for this solution is 4.255*10^-12
Explanation:
We are given
[H+] = 2.35 × 10-3 M
we need to find the concentration of [OH-]
we know from Equilibrium
[H+][OH-] = 10^-14
[OH-] = 10^14/2.35*10^10^-3
[OH-] = 0.4255*10^-11
[OH] = 4.255*10^-12
Therefore the Concentration of [OH-] for this solution is 4.255*10^-12
