Answer:
I2 + 2S2O3^2- --------> S4O6^2- + 2I^-
Explanation:
The correct equation is;
2Na2S2O3 + I2 → Na2S4O6 + 2NaI
Oxidation half equation;
2S2O3^2- --------> S4O6^2- + 2e-
Reduction half equation;
I2 + 2e ----------> 2I^-
Overall balanced redox reaction equation;
I2 + 2S2O3^2- --------> S4O6^2- + 2I^-
