Answer:
[tex]\frac{x}{x+2} - \frac{4}{x-2}=1\\or, \frac{x(x-2)}{(x+2)(x-2)} -\frac{4(x+2)}{(x+2)(x-2)}=1\\or, \frac{x^2-2x}{x^2-4} -\frac{(4x+8)}{x^2-4} =1\\or, \frac{x^2-2x-(4x+8)}{x^2-4} =1\\or, \frac{x^2-2x-4x-8}{x^2-4}=1\\or, {x^2-6x-8} =x^2-4\\or, -6x-8=-4\\or, 3x+4=2\\or, 3x = -2\\or, x =\frac{-2}{3}[/tex]
