Respuesta :
Answer:
a)    a = 3.72 m / s², b)   a = -18.75 m / s²
Explanation:
a) Let's use kinematics to find the acceleration before the collision
       v = v₀ + at
as part of rest the vâ‚€ = 0
       a = v / t
Let's reduce the magnitudes to the SI system
       v = 115 km / h (1000 m / 1km) (1h / 3600s)
       v = 31.94 m / s
       v₂ = 60 km / h = 16.66 m / s
l
et's calculate
       a = 31.94 / 8.58
       a = 3.72 m / s²
b) For the operational average during the collision let's use the relationship between momentum and momentum
      I = Δp
      F Δt = m v_f - m v₀
      F = [tex]\frac{m ( v_f - v_o)}{t}[/tex]
      F = m [16.66 - 31.94] / 0.815
      F = m (-18.75)
Having the force let's use Newton's second law
      F = m a
      -18.75 m = m a
       a = -18.75 m / s²
