jackgolden5788 jackgolden5788

09-02-2021
Engineering

contestada

R1 = 2Ω, R2 = 6Ω , R3= 2 Ω
Vbattery = 40 V
What is the voltage drop across the 2nd resistor (V2)?
A. 8V
B. 4V
C. 1.5V
D. 24V

Respuesta :

Perplexed20 Perplexed20

09-02-2021

I= E/R. 40v/10 ohms = 4 amps

E=IxR. 4x6= 24

So Answer is D. 24 volts

By proportional: series total is 10 ohms, R2, 6 ohms is 60%. .6x40=24

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