Answer:
6
Step-by-step explanation:
Given the expression sin(9z − 1) = cos(6z + 1), for 0 < z ≤ 90, we are to find z
Note that sin theta = cos(90-thetsa)
sin(9z − 1) = cos(6z + 1)
cos (90 - (9z-1)) = cos(6z + 1)
cos (90 - 9z+1)) = cos(6z + 1)
cos (91-9z) = cos(6z + 1)
Cos will cancel out to have;
91-9z = 6z+1
-9z - 6z = 1-91
-15z = -90
z = 90/15
z = 6
Hence the value of z is 6
