Answer:
MnSOâ‚„.7Hâ‚‚O
Explanation:
To solve this question, we need to convert the mass of the dehydrated MnSOâ‚„. The difference between mass of the hydrate and dehydrated compound is the mass of water. With the mass we can find the moles of water and the formula of the hydrate:
Moles MnSOâ‚„ -Molar mass: 151g/mol-:
17.51g * (1mol / 151g) = 0.116 moles
Moles Hâ‚‚O -Molar mass: 18g/mol-:
32.14g-17.51g = 14.63g * (1mol / 18g) = 0.813 moles
The ratio of moles MnSOâ‚„: Moles Hâ‚‚O represent the amount of water molecules in the hydrate:
0.813mol / 0.116mol = 7 molecules of water.
The hydrate formula is:
