Answer:
[tex]x^2 + (y-11)^2 = 5[/tex]
Step-by-step explanation:
Completing the square gives us that
[tex]x^2+y^2-22y+96=0\\x^2 + (y-11)^2 - 11^2 + 96 = 0\\x^2 + (y-11)^2 = 121 - 96\\x^2 + (y-11)^2 = 25\\x^2 + (y-11)^2 = 5[/tex]
Which is the standard form of a circle.
