First multiply both sides by two:
[tex]\frac{x}{2}*2+3*2\le 1*2[/tex]
Simplify:
[tex]x+6 \leq 2[/tex]
Subtract 6 from both sides:
[tex]x+6-6 \leq 2-6[/tex]
Simplify again:
[tex]x \leq -4[/tex]
Therefore, your solution should be:
[tex]\frac{x}{2}+3\le 1[/tex]=(-∞, -4]
