superbeast9012 superbeast9012

07-03-2021
Chemistry

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If 0.959J of heat is added to 0.88g of water, how much will its temperature increase

Respuesta :

samihaela samihaela

07-03-2021

Answer:

0.260 Celsius

Explanation:

q =c x m x (T2-T1)

c - specific heat of water 4.186 J/g.C

T2-T1 = q /(c x m) = 0.959 /(4.186 x 0.88) = 0.959/3.68 =0.260 C

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